3x/4=x^2/8

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Solution for 3x/4=x^2/8 equation: 


x in (-oo:+oo)

(3*x)/4 = (x^2)/8 // - (x^2)/8

(3*x)/4-((x^2)/8) = 0

3/4*x-1/8*x^2 = 0

DELTA = (3/4)^2-(-1/8*0*4)

DELTA = 9/16

DELTA > 0

x = ((9/16)^(1/2)-3/4)/(-1/8*2) or x = (-(9/16)^(1/2)-3/4)/(-1/8*2)

x = 0 or x = 6

x in { 0, 6 }

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